Arithmetic Ability
Permutations and Combinations

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Q.

How many 6-digit even numbers can be formed from the digits 1, 2, 3, 4, 5, 6 and 7 so that the digits should not repeat and the second last digit is even ?

View Answer

Correct choice: B

Explanation:

Let last digit is 2 when second last digit is 4 remaining 4 digits can be filled in 120 ways, similarly second last digit is 6 remained 4 digits can be filled in 120 ways. so for last digit = 2, total numbers=240 Similarly for 4 and 6 When last digit = 4, total no. of ways =240 and last digit = 6, total no. of ways =240 so total of 720 even numbers are possible.
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