Arithmetic Ability
Permutations and Combinations

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Q.

In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there ?

View Answer

Correct choice: C

Explanation:

We may have (1 boy and 3 girls)or(2boys and 2 girls)or(3 boys and 1 girl)or(4 boys). Required number of ways = (6C1x4 C3) + (6C2×4C2) + (6C3×4 C1) + (6C4) = (24+90+80+15) = 209.
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