Arithmetic Ability
Permutations and Combinations

21 / 181

Q.

There are 3 sections with 5 questions each. If four questions are selected from each section, the chance of getting different questions is ?

View Answer

Correct choice: D

Explanation:

Methods for selecting 4 questions out of 5 in the first section = 5 x 4 x 3 x 2 x 1/4 x 3 x 2 x 1 = 5. Similarly for other 2 sections also i.e 5 and 5 So total methods = 5 x 5 x 5 = 125.
21 / 181