Arithmetic Ability
Permutations and Combinations

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Q.

In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there?

View Answer

Correct choice: A

Explanation:

We may have (1 boy and 3 girls) or (2 boys and 2 girls) or (3 boys and 1 girl) or (4 boys). Required number of ways = (6C1*4C3)+(6C2*4C2)+(6C3*4C1)+6C4 = (6C1*4C1)+(6C2*4C2)+(6C3*4C1)+6C2 = 209.
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