Arithmetic Ability
Permutations and Combinations

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Q.

In the below word how many words are there in which R and W are at the end positions? RAINBOW

View Answer

Correct choice: D

Explanation:

When R and W are the first and last letters of all the words then we can arrange them in 5!ways. Similarly When W and R are the first and last letters of the words then the remaining letters can be arrange in 5! ways. Thus the total number of permutations = 2 x 5! = 2 x 120 = 240
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