Arithmetic Ability
Permutations and Combinations

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Q.

Out of seven consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed ?

View Answer

Correct choice: A

Explanation:

Number of ways of selecting (3 consonants out of 7) and (2 vowels out of 4) =( C37×C24 ) = 210. Number of groups, each having 3 consonants and 2 vowels =210 Each group contains 5 letters. Number of ways of arranging 5 letters among themselves = 5! = 120. Required number of words = (210 x 120) = 25200.
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