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Co - ordinate Geometry 3D Geometry

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If O is the origin and A is the point (a, b, c) then the equation of the plane through A and at right angles to OA is

A. a(x-a)-b(y-b)-c(z-c)= 0

B. a(x+a)+b(y+b)+c(z+c)= 0

C. a(x-a)+b(y-b)+c(z-c)= 0

D. a(x+a)+b(y+b)+c(z+c)= 0

E. None of the above

View Answer

Correct choice: C

Explanation:

Normal will be OA whose direction ratios are a - 0, b - 0, c - 0 i.e., a, b, c. It passes through A(a,b,c)
∴ Equation of required plane is,
a(x-a)+b(y-b)+c(z-c)= 0

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Eamcet Mathematics Co - ordinate Geometry 3D Geometry

Eamcet Mathematics
Co - ordinate Geometry 3D Geometry