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Algebra Permutations And Combinations
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Q.
The number of numbers that can be formed with the help of the digits 1, 2, 3, 4, 3, 2, 1 so that odd digits always occupy odd places, is
A.
24
B.
18
C.
12
D.
30
E.
None of the above
View Answer
Correct choice: B
Explanation:
The 4 odd digits 1, 3, 3, 1 can be arranged in the 4 odd places in 4!/2!2!=6 ways and 3 even digits 2, 4, 2 can be arranged in the three even places in 3!/2!=3 ways. Hence the required number of ways =6 × 3=18 .
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