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Q.
The number of ways in which ten candidates A
1
,A
2
,.........A
10
can be ranked such that A
1
is always above A
10
is
A.
5!
B.
2(5!)
C.
10!
D.
1/2 (10!)
E.
None of the above
View Answer
Correct choice: D
Explanation:
Without any restriction the 10 persons can be ranked among themselves in 10! ways; but the number of ways in which A
1
is above A
10
and the number of ways in which A
10
is above A
1
make up 10! . Also the number of ways in which A
1
is above A
10
is exactly same as the number of ways in which A
10
is above A
1
.
Therefore the required number of ways =1/2(10!) .
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