Arithmetic Ability
Time and Work

105 / 118

Q.

A group of workers was put on a job. From the second day onwards, one worker was withdrawn each day. The job was finished when the last worker was withdrawn. Had no worker been withdrawn at any stage, the group would have finished the job in 55% of the time. How many workers were there in the group?

View Answer

Correct choice: D

Explanation:

Let the number of workers be x. Now, Using work equivalence method, X + (X-1) + (X-2)+ . . . . + 1 = X *55% of X => [X * (X+1)] / 2 = X * (55X/100) [because, Series is in AP. Sum of AP = {No. of terms (first term+ last term)/2} ] Therefore, X = 10
105 / 118