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An observer 1.6 m tall is 20√3away from a tower. The angle of elevation from his eye to the top of the tower is 30º. The heights of the tower is:

A. 21.6 m

B. 23.2 m

C. 24.72 m

D. None of these

View Answer

Correct choice: A

Explanation:

Draw BE // CD Then, CE = AB = 1.6 m, BE = AC = DE/tan30=> DE = tan30 x 20√3=> DE = 1/√3x20√3 = 20 Therefore, CD = CE + DE = (1.6 + 20) m = 21.6 m.

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