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Q.
Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30º and 45º respectively. If the lighthouse is 100 m high, the distance between the two ships is:
A.
173 m
B.
200 m
C.
273 m
D.
300 m
View Answer
Correct choice: C
Explanation:
Let AB be the lighthouse and C and D be the positions of the ships. Then, AB = 100m, ∠ACB = 30°and∠ADB =45° AB/AC=tan30°=1/√3=>AC=AB*√3=100√3m AB/AD=tan45°=1=>AD=AB=100m CD=(AC+AD)=(100√3+100)m=100(v3+1)=100*2.73=273m
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