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Eamcet Mathematics
Trigonometry Properties of Triangles
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Q.
In ΔABC, b
2
cos 2A - a
2
cos 2B =
A.
b
2
-a
2
B.
b
2
-c
2
C.
c
2
-a
2
D.
a
2
+b
2
+c
2
E.
None of the above
View Answer
Correct choice: A
Explanation:
b
2
cos 2A -a
2
= b
2
(1-2sin
2
2(1 - 2 sin
2
B)
= b
2
- a
2
-2(b
2
sin
2
A -a
2
sin
2
B)= b
2
-a
2
.
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