Lessons

Eamcet Chemistry
2 nd Year : Unit 2.1 ( Solutions ) - Solution 1

51 / 62

Q.

The volume of 0.1N H2SO4 solution required to exactly neutralise 5.6g of KOH is

View Answer

Correct choice: D

Explanation:

5.6 gm = 5.6/56 = 0.1gm equivalents of KOH
For complete neutralization, equivalents of KOH = equivalents of H2SO4
i.e 0.1 = 0.1 × Vin lt.
∴ V = 1 lit
51 / 62