Lessons

General Aptitude
26.1 Permutation and Combination - General Questions

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Q.

Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?

View Answer

Correct choice: C

Explanation:

Number of ways of selecting (3 consonants out of 7) and (2 vowels out of 4)

      = (7C3 x 4C2)
 
  = 210.

Number of groups, each having 3 consonants and 2 vowels = 210.

Each group contains 5 letters.

Number of ways of arranging
5 letters among themselves
= 5!
  = 5 x 4 x 3 x 2 x 1
  = 120.

Required number of ways = (210 x 120) = 25200.

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