Lessons

General Aptitude
2.1 Height and Distance - General Questions

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Q.

An observer 1.6 m tall is 20√3 away from a tower. The angle of elevation from his eye to the top of the tower is 30º. The heights of the tower is:

View Answer

Correct choice: A

Explanation:

Let AB be the observer and CD be the tower.

Draw BE CD.

Then, CE = AB = 1.6 m,

      BE = AC = 203 m.

DE = tan 30º = 1
BE 3
DE = 203 m = 20 m.
3

CD = CE + DE = (1.6 + 20) m = 21.6 m.

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