Arithmetic Ability
Ratio and Proportion

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Q.

In a competitive exam, the number of passed students was four times the number of failed students. If there had been 35 fewer appeared students and 9 more had failed, the ratio of passed and failed students would have been 2 : 1, then the total number of students appered for the exam ?

View Answer

Correct choice: C

Explanation:

Let the number of failed students be x => Number of passed students = 4x So total number of students was 5x From the given data, If total number of students be 5x – 35 => 4x-35-9/x+9 = 2/1 => 4x – 44 = 2(x + 9) => 4x – 2x = 18 + 44 => x = 31 Total number = 31×5 = 155
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