Arithmetic Ability
Problems on Ages

43 / 93

Q.

A is three times as old as B. C was twice-as old as A four years ago. In four years' time, A will be 31. What are the present ages of B and C ?

View Answer

Correct choice: C

Explanation:

Let the age of A = A, B = B and C = C From given A = 3B 4 years ago, C-4 = 2(A-4); After 4 years A + 4 = 31; A = 27; sub in above B, we get B = 9 C = 2(27 - 4) + 4 = 46 + 4 = 50 Hence B = 9yrs and C = 50yrs.
43 / 93