Arithmetic Ability
Percentage

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Q.

At an examination in which maximum marks are 500. K got 10% less than L, L got 25% more than M and M got 20% less than N. If K got 360 marks what percentage of marks was obtained by N ?

View Answer

Correct choice: A

Explanation:

Let marks obtained by N = x M's marks = 0.80x L's marks = 1.25 (0.80x) K's marks = (0.90) (1.25) (0.80x) = 0.9x But 0.9x = 360 ⇒ x = 400 Percentage of Marks obtained by N = 400 x 100/500 = 80%
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