Arithmetic Ability
Calendar

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Q.

What was the day of the week on 28th May, 2006?

View Answer

Correct choice: A

Explanation:

28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006) Odd days in 1600 years = 0 Odd days in 400 years = 0 5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days (31[jan] + 28 [Feb]+ 31[Mar] + 30[April] + 28[May] ) = 148 days 148 days = (21 weeks + 1 day) 1 odd day. Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day. Given day is Sunday
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