Arithmetic Ability
 Probability

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Q.

A word consists of 9 letters; 5 consonants and 4 vowels.Three letters are choosen at random. What is the probability that more than one vowel will be selected ?

View Answer

Correct choice: B

Explanation:

3 letters can be choosen out of 9 letters in 9C3 ways. More than one vowels ( 2 vowels + 1 consonant or 3 vowels ) can be choosen in (4C2*5C1)+4C3 ways Hence,required probability = (4C2*5C1)+4C3/9C3 = 17/42
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